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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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C-program to find the factors of a number



In this C program we will find the factors of a number. The number will be taken from the user.

input:

The number(i.e: 5,6,9 etc.)

output:

The factors of the given number, by the user.

CODE---->


#include<stdio.h>
int main()
{
 int n,i;
 printf("Enter a number: ");
 scanf("%d",&n);
 if(n<0)
 {
  printf("\n%d is a negative number. Factors of a negative number doesn't exist.",n);
 }
 if(n==0)
 {
  printf("\nThe factors of 0 is = 0");
 }
 if(n>0)
 {
  printf("\nThe factors of %d are: ",n);
  for(i=1;i<=n;i++)
  {
   if(n%i==0)
    printf("%d ",i);
  }
 }
 return 0;
}

Download the C-Program file of this Program.

Don't just read, run on your pc !!!


RESULT :


Enter a number: 100

The factors of 100 are: 1 2 4 5 10 20 25 50 100
--------------------------------
Process exited after 4.536 seconds with return value 0
Press any key to continue . . .


Images for better understanding :

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