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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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C-program to check a number is ARMSTRONG number or not



In this C-program we will check the number is Armstrong number or not. The number will be taken from the user.

input:

The number(i.e : 567,610,7899 etc.)

output:

The number will be Armstrong or not

CODE---->


#include<stdio.h>
#include<math.h>
int main() 
{
 int c=0,b,a=0,r=0,n;
 printf(" Please,Enter a number : "); 
 scanf("%d",&n);
 b=n; 
 while(n!=0)
 {
  n=n/10;
  ++c;
 }
 n=b;
 while(n!=0)
 {
  r=n%10;
  a=a+pow(r,c);
  n=n/10;
 }
 if(b==a)
  printf("\n %d is a Armstrong number.",b);
 else
  printf("\n %d is not a Armstrong number.",b);
 return 0;
}

Download the C-Program file of this Program.

Don't just read, run on your pc !!!


RESULT :

 Please,Enter a number : 153

 153 is a Armstrong number.
--------------------------------
Process exited after 2.701 seconds with return value 0
Press any key to continue . . .


Images for better understanding :

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