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C programs QnA

Q. If sum of two integer is 14 and if one of them is 8 then find other integer. Ans: Well, this is very simple. Simply, one integer is 8 and sum of two integers is 14. So, we need to subtract the number 8 from their sum of 14 to get the second number. So, the second number is: 14 - 8 = 6 C-Program of this task Code---> #include<stdio.h> int main () { int num1 = 8 , num2 , sum = 14 ; num2 = sum - num1 ; printf ( "The second number is: %d" , num2 ); return 0 ; }
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C-program to calculate the GCD of two numbers.



In this C-program we will calculate the GCD of two numbers. This is the easiest way to calculate GCD for both Negative and Positive numbers. [This is almost the same program to calculate the LCM of two numbers.(We will calculate the LCM of two numbers in our next program.)] The numbers will be taken from the user.

input:

The numbers.(i.e : 20,25,40 etc.)

output:

The GCD of two numbers given by the user.

CODE---->


#include<stdio.h>
#include<conio.h>
 main()
{
int copy_num_1,copy_num_2,num_1,num_2,gcd,i ;
printf("Please, Enter two numbers : ");
scanf("%d%d",&num_1,&num_2);
copy_num_1=num_1;
copy_num_2=num_2;
//copying numbers , (entered by user) for future use.
if(num_1<0)
num_1=(num_1)*(-1);
if(num_2<0)
num_2=(num_2)*(-1);
//here, we are converting negative numbers(if any, entered by user), so that, we can calculate the gcd for both positive and negative numbers.
for(i=1;i<=num_1 && i<=num_2;i++)
{
if(num_1%i==0 && num_2%i==0)
gcd=i;
}
printf("\nThe GCD of %d and %d is : %d",copy_num_1,copy_num_2,gcd);
getch();
}



Don't just read, write it, run it.....

RESULT:



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