Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C-program we will check a number is Perfect number or not. The number will be taken from the user.
input:
The number .output:
The number will be Perfect number or not.CODE---->
#include<stdio.h>#include<conio.h>
main()
{
int num,n,i,sum=0;
printf(" Please,Enter a number \(to check whether it is Perfect number or Not\) : ");
scanf("%d",&num);
n=num;
for(i=1;i<=(n-1);i++)
{
if(n%i==0)
sum=sum+i;
}
if(sum==num)
printf("\n %d is a perfect number.",num);
else
printf("\n %d is not a perfect number.",num);
getch();
}
RESULT:
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