Skip to main content

Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
Post a Comment

C-program to calculate the LCM of two numbers.



In this C-program we will calculate the LCM of two numbers. This is the easiest way to calculate LCM for both Negative and Positive numbers. The numbers will be taken from the user.

input:

The numbers.(i.e : 20,25,40 etc.)

output:

The LCM of two numbers given by the user.

CODE---->


#include<stdio.h>
#include<conio.h>
 main()
{
int copy_num_1,copy_num_2,num_1,num_2,gcd,lcm=0,i ;
printf("Please, Enter two numbers : ");
scanf("%d%d",&num_1,&num_2);
copy_num_1=num_1;
copy_num_2=num_2;
//copying numbers , (entered by user) for future use.
if(num_1<0)
num_1=(num_1)*(-1);
if(num_2<0)
num_2=(num_2)*(-1);
//here, we are converting negative numbers(if any, entered by user), so that, we can calculate the lcm for both positive and negative numbers.
for(i=1;i<=num_1 && i<=num_2;i++)
{
if(num_1%i==0 && num_2%i==0)
gcd=i;
}
lcm=num_1*num_2/gcd;
//relation between lcm and gcd. so, we can get the lcm using this formula.
printf("\nThe LCM of %d and %d is : %d",copy_num_1,copy_num_2,lcm);
getch();
}



Don't just read, write it, run it.....

RESULT:



Comments

Post a Comment

Popular posts from this blog

Linear Queue Program in C-Language

In this C program we will perform operations over Linear Queue ( i.e: Data insert Operation, Data remove Operation and display Operation ). The Choice( i.e: data insert,remove or display ) will be made by the user and The Number will be taken from the user( i.e: For Data insert Operation ). input: The Choice(i.e Data insert, remove or display) & The Number (integers) (i.e. for Data insert Operations) (15,10,128 etc.) output: The Operations will be excecuted as choosen by the user. CODE----> #include<stdio.h> #include<stdlib.h> #define MAXSIZE 10 int Q [ MAXSIZE ], front =- 1 , rear =- 1 ; void qinsert ( int x ) { if ( rear == MAXSIZE - 1 ) printf ( "\n Queue is Full." ); else if ( front ==- 1 ) { front = 0 ; rear = 0 ; Q [ front ]= x ; } else { rear ++; Q [ rear ]= x ; } } void qdelete () { if ( front ==- 1 ) printf ( "\n Queue is Empty." ); else if ( front == rear ) { printf ( ...
2 comments
Read more

Calculate sum of 5 numbers using Array in C-language

In this C -program we will scan the numbers using array and then we will calculate the sum of the given numbers, also using array. The numbers will be taken from the user. input: 5 numbers.(i.e : 5,6,9,56,548) output: The sum of the given numbers will be printed on the screen. CODE----> #include<stdio.h> #include<stdlib.h> main() { int arr[5],i,sum=0; printf ("       Enter Five numbers : "); for ( i=0 ; i<5 ; i++ ) {       scanf (" %d ",&arr[i]); } for ( i=0 ; i<5 ; i++ ) {      sum=sum+arr[i]; } printf (" \n      The sum of the given 5 numbers is : %d\n ",sum); system (" pause "); } Don't just read, write it, run it..... RESULT :
3 comments
Read more

C-program of printing "Hello World", 10 times on the screen.

In this C program we will print "Hello World", 10 times on the screen. We will use "body-less-loop" for this C-Program. "Body-less-loop" : it means that the inner part(code block to be executed) of the loop will be empty and the loop will have a semi-colon(;) in it's end. i.e: for ( .....  ; .....  ; .....  ) ; input: Null. output: "Hello World" will be printed on the screen, 10 times. CODE----> #include<stdio.h> int main() {      int i;      for( i=1 ; i ;printf( "   Hello World ! \n ", i++ )) ;      return 0 ; } Don't just read, write it, run it..... RESULT :
12 comments
Read more