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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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C-program of calculate the sum of natural numbers up to N



In this C-program we will calculate the sum of natural numbers up to N. The number(N) will be taken from the user.

input:

The number.(i.e : 5,10,15 etc.)

output:

The sum up to N.

CODE---->


#include<stdio.h>
#include<conio.h>
 main()
{
int num,sum=0,i ;
printf("Please, Enter a positive number : ");
scanf("%d",&num);
if(num<0)
printf("\nYou have Entered a negative number. Please, try again.");
else
{
for(i=1;i<=num;i++)
sum=sum+i;
printf("\nThe sum of upto %d is : %d",num,sum);
}
getch();
}



Don't just read, write it, run it.....

RESULT:



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