Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
Java Stream API — Get Even Numbers
Example 1 — Filter even numbers from a list
Creates a list, uses Stream to filter evens, and prints them.
import java.util.*;
import java.util.stream.*;
public class EvenNumbersStream {
public static void main(String[] args) {
// Create a list of numbers
List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
// Use Stream API to filter even numbers
List<Integer> evenNumbers = numbers.stream()
.filter(n -> n % 2 == 0)
.collect(Collectors.toList());
// Print the even numbers
System.out.println("Even numbers: " + evenNumbers);
}
}
Example 2 — Use IntStream.rangeClosed over a range
Generates numbers in a range and prints the evens directly.
import java.util.stream.*;
public class EvenNumbersStreamRange {
public static void main(String[] args) {
System.out.println("Even numbers from 1 to 20:");
IntStream.rangeClosed(1, 20)
.filter(n -> n % 2 == 0)
.forEach(System.out::println);
}
}
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