Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C-program we will print the alphabets A to Z , using loop.
input:
Null.output:
print A to ZCODE---->
#include<stdio.h>
#include<conio.h>
main()
{
char char_end='Z', char_initial ;
for(char_initial='A';char_initial<=char_end;char_initial++)
printf("%c ",char_initial);
getch();
}
RESULT:
Write a C program to print all natural numbers from 1 to n using for loop.
ReplyDeleteCode of given problem:
int main()
{
int i=1,n;
printf("Enter the number to print all natural number till that entered number\t");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
printf("%d\t",i);
}
return 0;
}
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