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In this C -program we will Print the following Pattern made of 1 and 2 . The no. of rows will be taken from the user. 1 12 121 1212 12121 input: The number of rows. output: The Pattern will be printed on the screen in the given range. CODE----> #include<stdio.h> int main () { int i , j , n ; printf ( "Please,Enter the no. of rows: " ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { for ( j = 1 ; j <= i ; j ++) { if ( j % 2 != 0 ) printf ( "1" ); else printf ( "2" ); } printf ( "\n" ); } return 0 ; } Download the C-Program file of this Program. Don't just read, run on your pc !!! RESULT : Please,Enter the no. of rows: 7 1 12 121 1212 12121 121212 1212121 -------------------------------- Process exited after 1.527 seconds with return value 0 Press any key to continue . . . Images for better understanding :

In this C -program we will Print the following Pattern made of A and B . The no. of rows will be taken from the user. A AB ABA ABAB ABABA input: The number of rows. output: The Pattern will be printed on the screen in the given range. CODE----> #include<stdio.h> int main () { int i , j , n ; printf ( "\nPlease,Enter the no. of rows: " ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { for ( j = 1 ; j <= i ; j ++) { if ( j % 2 != 0 ) printf ( "A" ); else printf ( "B" ); } printf ( "\n" ); } return 0 ; } Download the C-Program file of this Program. Don't just read, run on your pc !!! RESULT : Please,Enter the no. of rows: 10 A AB ABA ABAB ABABA ABABAB ABABABA ABABABAB ABABABABA ABABABABAB -------------------------------- Process exited after 5.282 seconds with return value 0 Press any key to continue . . . Images for better unders...

In this C program we will multiply two matrices and print the result on the screen.The elements of the matrices will be taken from the user. input: The elements of matrices. output: The Multiplication of the two matrices. CODE----> #include <stdio.h> void input ( int first [ 10 ][ 10 ], int second [ 10 ][ 10 ], int r1 , int c1 , int r2 , int c2 ) { int i , j ; printf ( "\nEnter elements of matrix 1:\n" ); for ( i = 0 ; i < r1 ; i ++) { for ( j = 0 ; j < c1 ; j ++) { printf ( "Enter data: " ); scanf ( "%d" ,& first [ i ][ j ]); } } printf ( "\nEnter elements of matrix 2:\n" ); for ( i = 0 ; i < r2 ; i ++) { for ( j = 0 ; j < c2 ; j ++) { printf ( "Enter data: " ); scanf ( "%d" ,& second [ i ][ j ]); } } } void multiply ( int first [ 10 ][ 10 ], int second [ ...

In this C program we will add two matrices(3*3) and print the result on the screen.The elements of the matrices will be taken from the user. input: The elements of matrices(3*3). output: The Sum of the two matrices. CODE----> #include<stdio.h> int main () { int mat1 [ 10 ][ 10 ], mat2 [ 10 ][ 10 ], mat3 [ 20 ][ 20 ], i , j ; printf ( "Please,Enter the first matrix--->> " ); for ( i = 1 ; i <= 3 ; i ++) { for ( j = 1 ; j <= 3 ; j ++) { printf ( "\nPlease,Enter data: " ); scanf ( "%d" ,& mat1 [ i ][ j ]); } } printf ( "\n\nPlease,Enter the second matrix--->> " ); for ( i = 1 ; i <= 3 ; i ++) { for ( j = 1 ; j <= 3 ; j ++) { printf ( "\nPlease,Enter data: " ); scanf ( "%d" ,& mat2 [ i ][ j ]); } } printf ( "\n\nThe sum of the matrices --->> \n" ); for ( i = 1 ; i <= 3 ; i ++) { for ( j = 1 ; j <= 3 ; j ++)...

The Dice Game Description: The Dice Game is the result of different and innovative thinking. The idea is to play a game, made by a simple code in C-Language. No graphics, just a simple game. Nothing more to say. Simply, download the code, compile it and start playing. The download link is given below: Download the C-Program file of this Game.             Compile and Play Rules : 1.Every Player gets 100$. 2. Every Player bet 10$ on a number. 3. Dice will be thrown. A random number will generate. 4. The closest bet number to the dice will win. 5.If both players bet the same number, no prize. Better Luck, Next time !! 6. If no money left, then you have lost. 7. The last Player with money, WINS !!! 8. In the Best of 3 match, two-player(s) will be fighting for only three rounds. The major winner of those three rounds will win. However, if both players win only 1 round or no round, then it will call a ...