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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Time delay in C Language




In this C program we will delay the program for a period of time. The period of time(in seconds) will be taken by the user.

input:

The amount of time(in seconds).

output:

The delay.

CODE---->


#include<stdio.h>
#include<time.h>
void delay(int milli_sec) 
{
    // Stroing start time
    clock_t start_time=clock();
    // looping till required time is not acheived
    while(clock()<start_time+milli_sec);
}
int main()
{
 int sec,milli_sec;
 printf("Please, Enter the time(in seconds) you want to delay: ");
 scanf("%d",&sec);
 // transforming seconds into milli_seconds
 milli_sec=sec*1000;
 delay(milli_sec);
 printf("\n\nYour System has been delayed by %d seconds.",sec);
 return 0;
}

Download the C-Program file of this Program.

Don't just read, run on your pc !!!


RESULT :


Please, Enter the time(in seconds) you want to delay: 5


Your System has been delayed by 5 seconds.
--------------------------------
Process exited after 7.358 seconds with return value 0
Press any key to continue . . .


Images for better understanding :


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