Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will read a file and count how many characters, spaces, tabs and newlines are present in a text file. This file's location is same with the c-program file's location, means, they both in a same folder. This program counts every character including tabs, spaces, newlines as a character.
input:
The already exists text File.output:
The number of characters, tabs, spaces and newlines present in that file.
CODE---->
#include<stdio.h>
int main()
{
int lines=0,tabs=0,spaces=0,chars=0;
char ch;
FILE *fp;
fp=fopen("test.txt", "r");
while(1)
{
ch=fgetc(fp);
if(ch==EOF)
break;
chars++;
if(ch==' ')
spaces++;
if(ch=='\n')
lines++;
if(ch=='\t')
tabs++;
}
fclose(fp);
printf("Number of characters: %d",chars);
printf("\nNumber of blanks: %d", spaces);
printf("\nNumber of tabs: %d", tabs);
printf("\nNumber of lines: %d",lines);
return 0;
}
Download the C-Program file of this Program.
RESULT :
Number of characters: 89 Number of blanks: 14 Number of tabs: 1 Number of lines: 2 -------------------------------- Process exited after 0.5392 seconds with return value 0 Press any key to continue . . .
Images for better understanding :
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