Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will calculate the Binary Equivalent of a Decimal Number Using Bitwise Operator and then we will print the result on the screen. The Number will be taken from the user.
N:B This Program is created for upto 8-bit binary number(
i.e: Range = 0 to 28-1 = 0 to 255).
input:
The Number (integers) (i.e. 15,10,128 etc.)output:
The binary equivalent of the decimal number, will be printed on the screen.
CODE---->
#include<stdio.h>
int main()
{
int n,i,x;
printf(" Please, Enter a Number : ");
scanf("%d",&n);
printf("\n ");
for(i=7;i>=0;i--)
{
x=n&(1<<i);
if(x==0)
printf("0");
else
printf("1");
}
return 0;
}
RESULT:
its really amazing tool to convert binary number into decimal number
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