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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Reading From a File in C-Language



In this C program we will Read the content of a text-file(.txt) by printing the content of the text-file(.txt)in the screen.

input:

NULL.

output:

The content of the text-file(.txt) will be printed on the screen and then we can read the content.

CODE---->


#include<stdio.h>
#include<stdlib.h>
int main()
{
 FILE *fp;
 char ch;
 fp=fopen("hello.txt", "r");
 if(fp==NULL)
 {
  printf("  Unable to open File.");
 }
 else
 {
  ch=fgetc(fp);
  while(ch!=EOF)
  {
   printf("%c",ch);
   ch=fgetc(fp);
  }
 }
 fclose(fp);
 return 0;
}

N.B. : In this C-Program the used text-file(.txt) and the C-Program file was stored in the same directory or path. So, if you want to open the text-file(.txt) stored in any other directory, path or folder, then, you have to declare the whole path or directory in the program.(i.e : fp=fopen("C:\\Users\\ADMIN\Desktop\\...the directory...\\file_name.txt")). The directory of a text-file(.txt) can be found by it's Property
Don't just read, write it, run it.....

RESULT:


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