Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will Read the content of a text-file(.txt) by printing the content of the text-file(.txt)in the screen.
input:
NULL.output:
The content of the text-file(.txt) will be printed on the screen and then we can read the content.
CODE---->
#include<stdio.h>
#include<stdlib.h>
int main()
{
FILE *fp;
char ch;
fp=fopen("hello.txt", "r");
if(fp==NULL)
{
printf(" Unable to open File.");
}
else
{
ch=fgetc(fp);
while(ch!=EOF)
{
printf("%c",ch);
ch=fgetc(fp);
}
}
fclose(fp);
return 0;
}
N.B. : In this C-Program the used text-file(.txt) and the C-Program file was stored in the same directory or path. So, if you want to open the text-file(.txt) stored in any other directory, path or folder, then, you have to declare the whole path or directory in the program.(i.e :
fp=fopen("C:\\Users\\ADMIN\Desktop\\...the directory...\\file_name.txt")). The directory of a text-file(.txt) can be found by it's Property RESULT:
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