Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will check the 3 numbers and find the Largest number among them. We will also check all the possible conditions (i.e: if there is more than one Largest number exists, means two numbers which has equal values and larger than the third number, it will be shown in this Program and if all the numbers has same value, then, it will be also shown in this Program. The three numbers(integers)(i.e: 55, 64, 11) will be taken from the user.
input:
The three numbers(integers)(i.e: 55, 64, 11)output:
The Largest number(s) will be printed on the screen.
CODE---->
#include<stdio.h>
int main()
{
int a,b,c;
printf("Enter the values of 3 numbers : ");
scanf("%d%d%d",&a,&b,&c);
if(a>b)
{
if(a>c)
printf("\n The First Number is Largest : %d",a);
else if(a==c)
printf("\n Both Number 1 and Number 3 are Equal and Largest : %d",a);
else
printf("\n Number 3 is Largest : %d",c);
}
else if(b==a)
{
if(a==c)
printf("\n All The Numbers are Equal : %d",a);
else if(c>a)
printf("\n Number 3 is Largest : %d",c);
else
printf("\n Both Number 1 and Number 2 are Equal and Largest : %d",a);
}
else
{
if(b>c)
printf("\n Number 2 is Largest : %d",b);
else if(b==c)
printf("\n Both Number 2 and Number 3 are Equal and Largest : %d",b);
else
printf("\n Number 3 is Largest : %d",c);
}
return 0;
}
RESULT:
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