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C programs QnA

Q. If sum of two integer is 14 and if one of them is 8 then find other integer. Ans: Well, this is very simple. Simply, one integer is 8 and sum of two integers is 14. So, we need to subtract the number 8 from their sum of 14 to get the second number. So, the second number is: 14 - 8 = 6 C-Program of this task Code---> #include<stdio.h> int main () { int num1 = 8 , num2 , sum = 14 ; num2 = sum - num1 ; printf ( "The second number is: %d" , num2 ); return 0 ; }
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C-Program Of "Finding the LARGEST Number among 3 numbers and Checking all the possible Conditions."



In this C program we will check the 3 numbers and find the Largest number among them. We will also check all the possible conditions (i.e: if there is more than one Largest number exists, means two numbers which has equal values and larger than the third number, it will be shown in this Program and if all the numbers has same value, then, it will be also shown in this Program. The three numbers(integers)(i.e: 55, 64, 11) will be taken from the user.

input:

The three numbers(integers)(i.e: 55, 64, 11)

output:

The Largest number(s) will be printed on the screen.

CODE---->


#include<stdio.h>
 int main()
{
   int a,b,c;
   printf("Enter the values of 3 numbers : ");
   scanf("%d%d%d",&a,&b,&c);
  if(a>b)
  {
    if(a>c)
    printf("\n The First Number is Largest : %d",a);
    else if(a==c)
    printf("\n Both Number 1 and Number 3 are Equal and Largest :      %d",a);
    else
    printf("\n Number 3 is Largest : %d",c);
  }
  else if(b==a)
  {
     if(a==c)
    printf("\n All The Numbers are Equal : %d",a);
    else if(c>a)
    printf("\n Number 3 is Largest : %d",c);
    else
    printf("\n Both Number 1 and Number 2 are Equal and Largest :      %d",a);
  }
  else
  {
    if(b>c)
    printf("\n Number 2 is Largest : %d",b);
    else if(b==c)
    printf("\n Both Number 2 and Number 3 are Equal and Largest :      %d",b);
    else
    printf("\n Number 3 is Largest : %d",c);
  }
  return 0;
}



Don't just read, write it, run it.....

RESULT:


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