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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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print the following pattern in C-Language



In this C-program we will Print the following Pattern made of asterisk(*). The no. of rows will be taken from the user.

*****
 ****
  ***
   **
    *

input:

The number of rows.

output:

The Pattern will be printed on the screen in the given range.

CODE---->

#include<stdio.h>
#include<stdlib.h>
int main()
{
	int i,j,k,n,space=0;
	printf("Please, Enter the no. of rows : ");
	scanf("%d",&n);
	if(n<=0)
	{
		printf("Wrong input.");
		exit(0);
	}
	for(i=n;i>0;i--)
	{
		for(k=space;k>0;k--)
			printf(" ");
		for(j=i;j>0;j--)
			printf("*");
		space=space+1;
		printf("\n");
	}
	return 0;
}

~ The Space variable is actually used for new line.
Download the C-Program file of this Program.

Don't just read, run on your pc !!!

RESULT :


Please, Enter the no. of rows : 5
*****
 ****
  ***
   **
    *

--------------------------------
Process exited after 2.825 seconds with return value 0
Press any key to continue . . .


Images for better understanding :

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