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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Perfect Numbers in a Range in C-Language



In this C-program we will check the Perfect numbers in a given Range and print them on the screen. The lower range and the upper range will be taken from the user.

input:

The Lower Range and the Upper Range.

output:

The Perfect numbers will be printed on the screen in the given range.

CODE---->

#include<stdio.h>
#include<stdlib.h>
int perfect(int x)
{
 int i,sum=0;
 if(x==0)
  return 0;
 for(i=1;i<=(x-1);i++)
 {
  if(x%i==0)
   sum=sum+i;
 }
 if(sum==x)
  return 1;
 else
  return 0;
}
int main()
{
 int num,i,lr,ur,check;
 printf("\n Please, Enter the Lower range : ");
 scanf("%d",&lr);
 printf("\n Please, Enter the Higher range : ");
 scanf("%d",&ur);
 printf("\n The Perfect numbers are : ");
 for(i=lr;i<=ur;i++)
 {
  check=perfect(i);
  if(check==1)
   printf(" %d ",i);
 }
 printf("\n");
}




Don't just read, write it, run it.....

RESULT:



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