Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will calculate the Binary Equivalent of a Decimal Number Using Bitwise Operator and then we will print the result on the screen. The Number will be taken from the user. N:B This Program is created for upto 8-bit binary number ( i.e: Range = 0 to 2 8 -1 = 0 to 255 ). input: The Number (integers) (i.e. 15,10,128 etc.) output: The binary equivalent of the decimal number, will be printed on the screen. CODE----> #include<stdio.h> int main () { int n , i , x ; printf ( " Please, Enter a Number : " ); scanf ( "%d" ,& n ); printf ( "\n " ); for ( i = 7 ; i >= 0 ; i --) { x = n &( 1 << i ); if ( x == 0 ) printf ( "0" ); else printf ( "1" ); } return 0 ; } Don't just read, write it, run it..... RESULT :