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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Bubble Sorting in C Language



In this C program we will sort(in ascending order) some elements and print the sorted order of the Array of elements, in the screen. The Number of elements to be entered in the Array will be taken from the user and also the values of the elements.

input:

The number of elements(integers) (i.e. 5,10,7 etc.) & the values of the elements(integers) (i.e. 51,10,74 etc.).

output:

The sorted(in Ascending Order) numbers will be printed on the screen.

CODE---->


#include<stdio.h>
int main()
{
 int a[50],n,i,j,t;
 printf("  Please, Enter the number of elements : ");
 scanf("%d",&n);
 for(i=0;i<n;i++)
 {
  printf("\n  Please, Enter data : ");
  scanf("%d",&a[i]);
 }
 for(i=0;i<n-1;i++)
 {
  for(j=0;j<=n-i-1;j++)
  {
   if(a[j]>a[j+1])
   {
    t=a[j];
    a[j]=a[j+1];
    a[j+1]=t;
   }
  }
 }
 printf("\n After sorting : ");
 for(i=0;i<n;i++)
 printf("%d  ",a[i]);
 return 0;
}




Don't just read, write it, run it.....

RESULT:


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