Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C program we will calculate the nPr or nCr and print the result, in the screen. The choice will be taken from the user. User can calculate nCr or nPr by choice.
If you are new in nPr or nCr and want to know about nPr or nCr,please, click below :
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input:
User's Choice. (i.e. 1.for nPr and 2.for nCr) & then, objects(n) and samples(r).output:
The Calculated result will be printed on the screen.
CODE---->
#include<stdio.h>
#include<conio.h>
#include<math.h>
#include<stdlib.h>
int npr();
int ncr();
int fact(int num3);
main()
{
int choice;
printf("*********Menu*********\n");
printf("1.nPr\n2.nCr\n\n");
printf("Please, Enter Your Choice : ");
scanf("%d",&choice);
if(choice==1)
npr();
if(choice==2)
ncr();
getch();
}
int npr()
{
int num1,num2,i,nr,answer_1,answer_2,answer_3;
printf("\nP(n,r) \n");
printf("Enter n(objects) :" );
scanf("%d",&num1);
printf("\nEnter r(sample) : ");
scanf("%d",&num2);
answer_1=fact(num1);
nr=num1-num2;
answer_2=fact(nr);
answer_3=answer_1/answer_2;
printf("\n P(n,r) : %d",answer_3);
}
int ncr()
{
int num1,num2,i,nr,answer_1,answer_2,answer_3,answer_4,answer_5;
printf("\nC(n,r) \n");
printf("Enter n(objects) :" );
scanf("%d",&num1);
printf("\nEnter r(sample) : ");
scanf("%d",&num2);
answer_1=fact(num1);
nr=num1-num2;
answer_2=fact(nr);
answer_3=fact(num2);
answer_4=answer_2*answer_3;
answer_5=answer_1/answer_4;
printf("\n C(n,r) : %d",answer_5);
}
int fact(int num3)
{
int i,ans=1;
for(i=1;i<=num3;i++)
{
ans=ans*i;
}
return ans;
}
RESULT:
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