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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Sum of two Integer numbers using function



In this C program we will calculate the summation of two numbers(int) using "Function" and print the result, in the screen. The two numbers will be taken from the user.

input:

Two numbers(int). (i.e. 15,23 etc.)

output:

Summation of the given numbers(int) will be printed on the screen.

CODE---->


#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
 int sum();     /* function declaration */
main()     /* main function */
{
      int choice;
      printf("**********WELCOME**********\n\n");
      printf("Please, select your choice.\n");
      printf("1.Addition(press 1, for addition)\n2.Exit(press 2,for quit)\n\n");
      printf("Please, Enter your choice : ");
      scanf("%d",&choice);
      if(choice==1)
      sum();     /* function call */
      if(choice==2)
      exit(0);
      getch();
}       /* end of main() function */
     /* function structure */
sum(){
      int num1,num2,result;
      printf("\nYou have selected addition option.\nPlease, Enter the 1st number : ");
      scanf("%d",&num1);
      printf("\nPlease, Enter the second number : ");
      scanf("%d",&num2);
      result=num1+num2;
      printf("\nThe result is : %d + %d = %d",num1,num2,result);
}



Don't just read, write it, run it.....

RESULT:


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