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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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Calculate the sum up to N numbers using Array in C-Language



In this C-program we will calculate the sum upto 'N' numbers using array. The numbers will be taken from the user.

input:

'N' numbers.(i.e : 9,56,548)

output:

The sum of the given numbers will be printed on the screen.

CODE---->


#include<stdio.h>
#include<stdlib.h>
 main()
{
int arr[50],i,n,sum=0;
printf("      How many numbers you want to enter ?\n ");
scanf("%d",&n);
printf("      Please,Enter the numbers : ");
for(i=0;i<n;i++)
{
     scanf("%d",&arr[i]);
}
for(i=0;i<n;i++)
{
     sum=sum+arr[i];
}
printf("\n      The sum of the given numbers is : %d\n",sum);
system("pause");
}



Don't just read, write it, run it.....

RESULT:



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