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Get Even Numbers Using Java Stream API

Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
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A Pattern using Asterisk(*) in C-Language



In this C-program we will Print a pattern using Asterisks(*). The no. of rows will be taken from the user. In the first Row the no. of spaces will be (n-1) [Here, we considered that, the user entered n no. of rows as input],and then a *. In the 2nd Row the number of Spaces will be decreased and the no. of * will be increased by 1. In that way, the last Row(nth row) have no Spaces and have all(n) *.

----*
---**
--***
-****
*****
► Here, - sign is used as Space for better understanding.

input:

The no. of Rows.

output:

The Pattern will be printed on the screen in the given range.

CODE---->

#include<stdio.h>
int main() 
{
 int i,j,k,n;
 printf("  Please, Enter the no. of Rows : ");
 scanf("%d",&n);
 for(i=1;i<=n;i++) 
 {
  for(j=n;j>i;j--) 
  {
   printf(" ");
  }
  for(k=1;k<=i;k++) 
  {
   printf("*");
  }
  printf("\n");
 }
 return 0;
}




Download the C-Program file of this Program.

Don't just read, write it, run it.....

RESULT:



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