Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C -program we will Print a pattern using Asterisks(*). The no. of rows will be taken from the user. In the first Row the no. of spaces will be (n-1) [Here, we considered that, the user entered n no. of rows as input],and then a * . In the 2nd Row the number of Spaces will be decreased and the no. of * will be increased by 1. In that way, the last Row(n th row) have no Spaces and have all(n) * . ----* ---** --*** -**** ***** ► Here, - sign is used as Space for better understanding. input: The no. of Rows. output: The Pattern will be printed on the screen in the given range. CODE----> #include<stdio.h> int main () { int i , j , k , n ; printf ( " Please, Enter the no. of Rows : " ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { for ( j = n ; j > i ; j --) { printf ( " " ); } for ( k = 1 ; k <= i ; k ++) { printf ( "*" ); } printf ( ...