Q. If sum of two integer is 14 and if one of them is 8 then find other integer. Ans: Well, this is very simple. Simply, one integer is 8 and sum of two integers is 14. So, we need to subtract the number 8 from their sum of 14 to get the second number. So, the second number is: 14 - 8 = 6 C-Program of this task Code---> #include<stdio.h> int main () { int num1 = 8 , num2 , sum = 14 ; num2 = sum - num1 ; printf ( "The second number is: %d" , num2 ); return 0 ; }
In this C -program we will check the Perfect numbers in a given Range and print them on the screen. The lower range and the upper range will be taken from the user. input: The Lower Range and the Upper Range. output: The Perfect numbers will be printed on the screen in the given range. CODE----> #include<stdio.h> #include<stdlib.h> int perfect ( int x ) { int i , sum = 0 ; if ( x == 0 ) return 0 ; for ( i = 1 ; i <=( x - 1 ); i ++) { if ( x % i == 0 ) sum = sum + i ; } if ( sum == x ) return 1 ; else return 0 ; } int main () { int num , i , lr , ur , check ; printf ( "\n Please, Enter the Lower range : " ); scanf ( "%d" ,& lr ); printf ( "\n Please, Enter the Higher range : " ); scanf ( "%d" ,& ur ); printf ( "\n The Perfect numbers are : " ); for ( i = lr ; i <= ur ; i ++) { check = perfect ( i ); if ( check == 1 ) printf ( " %d " , i ...