Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C -program we will check the Perfect numbers in a given Range and print them on the screen. The lower range and the upper range will be taken from the user. input: The Lower Range and the Upper Range. output: The Perfect numbers will be printed on the screen in the given range. CODE----> #include<stdio.h> #include<stdlib.h> int perfect ( int x ) { int i , sum = 0 ; if ( x == 0 ) return 0 ; for ( i = 1 ; i <=( x - 1 ); i ++) { if ( x % i == 0 ) sum = sum + i ; } if ( sum == x ) return 1 ; else return 0 ; } int main () { int num , i , lr , ur , check ; printf ( "\n Please, Enter the Lower range : " ); scanf ( "%d" ,& lr ); printf ( "\n Please, Enter the Higher range : " ); scanf ( "%d" ,& ur ); printf ( "\n The Perfect numbers are : " ); for ( i = lr ; i <= ur ; i ++) { check = perfect ( i ); if ( check == 1 ) printf ( " %d " , i ...