Java Stream API — Even Numbers (Full Screen) Java Stream API — Get Even Numbers Example 1 — Filter even numbers from a list Creates a list, uses Stream to filter evens, and prints them. Copy import java.util.*; import java.util.stream.*; public class EvenNumbersStream { public static void main(String[] args) { // Create a list of numbers List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10); // Use Stream API to filter even numbers List<Integer> evenNumbers = numbers.stream() .filter(n -> n % 2 == 0) .collect(Collectors.toList()); // Print the even numbers System.out.println( "Even numbers: " + evenNumbers); } } Example 2 — Use IntStream.rangeClosed ...
In this C -program we will check the number is Palindrome or not. The number will be taken from the user. input: The number(i.e : 567,610,7899 etc.) output: The number will be Palindrome or not CODE----> #include<stdio.h> int main () { int b , a = 0 , r = 0 , n ; printf ( " Please,Enter a number : " ); scanf ( "%d" ,& n ); b = n ; while ( n != 0 ) { r = n % 10 ; a = a * 10 + r ; n = n / 10 ; } if ( b == a ) printf ( "\n %d is a Palindrome number." , b ); else printf ( "\n %d is not a Palindrome number." , b ); return 0 ; } Download the C-Program file of this Program. Don't just read, run on your pc !!! RESULT : Please,Enter a number : 121 121 is a Palindrome number. -------------------------------- Process exited after 3.219 seconds with return value 0 Press any key to continue . . . Please,Enter a number : 122 122 is not a Palindrome number. -----------------...